General principle:
- If youβve got something on one side, you can move it to the other side, but with the opposite operation.
- Look for this principle in the key operations below. Then just remember the principle.
Key Operations:
Section titled βKey Operations:βAdd/Subtract x from both sides
Section titled βAdd/Subtract x from both sidesβYou can add or subtract x from both sides to move a number over to the other side of an equation.
If you start with
iβ1=5You can add a 1 to both sides:
iβ1+1=5+1You get
i=6You can divide both sides by the same number
Section titled βYou can divide both sides by the same numberβYou can divide both sides by x to move a number over to the other side of an equation.
If you start with
4i=20You can divide both sides by 4:
4iΓ·4=20Γ·4You get
i=5How to get rid of a pesky exponent
Section titled βHow to get rid of a pesky exponentβTo get rid of a pesky exponent, you can move it to the other side as a fraction.
For example,
(1+i)10=1.9becomes
1+i=1.9101ββοΈ Suppose you have a 10 year zero coupon bond with a face value of $1000 that is currently selling for $500. What is its YTM?
β When he says that something is βselling forβ $500, he means that that is its price, so PB = $500, F=$1000, T=10.
We just write down the bond pricing formula:
PBβ=(1+i)TFβ $500=(1+i)10$1000βThe first step that we do is the βswitcheroo:β
(1+i)10=$500$1000βRecopying, and simplifying we get:
(1+i)10=2Now we move the β10th powerβ exponent over to the other side as a βone 10th power:β
1+i=2101βYou can enter this in to a spreadsheet or Google as 2^(1/10). Do it exactly like that. donβt omit parentheses. πββοΈβPEMDAS is your friend! πβ
Therefore, i=7.177%.
To understand the switch

What you are really doing
Section titled βWhat you are really doingβYou can take the same exponent of both sides to get rid of an exponent. For example if one side of an equation is to the tenth power, you can take the 101βth power of both sides. This will give you what you want.
If you start with
(1+i)10=1.9You can take the βone tenthβ power of both sides:
(1+i)10101β=1.9101β)You get
i=5Plug and Chug
Section titled βPlug and ChugβIf you stuck, you can often solve the problem using βplug and chug.β With some practice, youβll find it easy!
- Identify the number you need and numbers you know.
- Need to know:
- Already know: Do you know an equation that connects the number you need to the numbers you know?
- Plug π the numbers you know into the equation.
- Algebraically solve for the needed quantity (βchugβ π). If you like, you can check β your algebra by plugging your answers back into the original equation.
- Think over π§ your result. Does it make sense based on what you learned in class?
I will often summarize these four steps with the following template:
Plug and chug:
1. Equation β
2. Plug π β
3. Solve π β
4. π§ β
Notes:
- Math fact: If you know all of the numbers in a formula except one, you can generally use algebra to find the last number.
- This method is just how you solved basic word problems in Algebra class. We realize that it may have been years or even decades since you took algebra, so weβre trying to make it as βstep by stepβ as possible!
βοΈ Suppose that a given company has an ROA of 1.5% and Assets of $1 billion. What is the firmβs profit after taxes?
β Solving this is easy. You just find an equation, plug numbers into it and do very basic algebra.
Plug and chug:
1. Equation β Weβll use the definition of ROA, β
ROA = ProfitAfterTaxes/Asset
2. Plug π β
1.5% = ProfitAfterTaxes/$1B
3. Solve π β
1.5%Γ$1B = ProfitAfterTaxes
ProfitAfterTaxes = 1.5%Γ$1B = $15M
4. π§ β Letβs check our work by plugging back into the formula.
ROA = ProfitAfterTaxes/Asset
ROA = $15M/$1B = .015 = 1.5%
βοΈ Suppose that total deposits in the economy increase by $5B, but the money supply only increases by $4.5B. What happened to Cash in the hands of the public?
β
Plug and chug:
1. Equation β
ΞMS=ΞDeposits+ΞCash Held by Public
2. Plug π β
$4.5B=$5B+ΞCash Held by Public
3. Solve π β
$4.5B-$5B=ΞCash Held by Public
ΞCash Held by Public = $4.5B-$5B = -$.5B
4. π§ β You can plug the numbers back in to check.
βοΈ Suppose that rf = 5%, the market risk premium, Erm - rf, is 6%, and for a given stock its expected return, Ers, is 9%. What is Ξ²?
β
Plug and chug:
1. Equation β
E(rS)=rF+Ξ²[E(rM)-rF]
2. Plug π β
9%=5%+Ξ²[6%]
3. Solve π β
9%-5%=Ξ²[6%]
4%=Ξ²[6%]
4%\div6%=Ξ²
Ξ² = 4/6 = .66
4. π§ β
Math worksheet
Section titled βMath worksheetβFeedback? Email rob.mgmte2000@gmail.com π§. Be sure to mention the page you are responding to.